This math problem can easily be answered by any child who has attended kindergarten.
However, within the axiom system designed by Qiao Yu, because N(1) = {N_α,β(1) ∣ (α,β) ∈ all modal spaces}, N(2) = {N_α,β(2) ∣ (α,β) ∈ all modal spaces}.
Therefore, the equation becomes: N_α,β(1) ⊕ α,β N_α,β(1) = N_α,β(2)
If modal parameters are substituted, it can further transform into: N_α,β(1) ⊕ α,β N_α,β(1) = N_α,β(2 + δα,β)
Once in a periodic modal space, a conclusion can be drawn that N_α,β(1) ⊕ α,β N_α,β(1) = N_α,β(0).
Because this means that 1+1 returns to a modal value of "zero," forming a closed structure in the modal space.
Wait a moment...
So if one must provide a general solution for 1+1 within this axiom system, it is: N(1+1) = {N_α,β(1) ⊕ α,β N_α,β(1) ∣ (α,β) ∈ all modal spaces}
To the average person, this seems like complicating a simple problem.
But for a mathematician, especially one studying number theory, it feels incredibly flexible!
